From 32c6c776087b326e4f18db585d13f87d8d09a597 Mon Sep 17 00:00:00 2001 From: =?UTF-8?q?=D0=9D=D0=B8=D0=BA=D0=B8=D1=82=D0=B0=20=D0=9C=D0=B0=D1=80?= =?UTF-8?q?=D0=BA=D0=BE=D0=B2?= Date: Sun, 12 Oct 2025 21:50:31 +0300 Subject: [PATCH] report is done --- TEMA4/report.md | 2 +- TEMA5/Figure_1.png | Bin 0 -> 29718 bytes TEMA5/report.md | 324 +++++++++++++++++++++++++++++++++++++++++++++ TEMA5/task.md | 35 +++++ 4 files changed, 360 insertions(+), 1 deletion(-) create mode 100644 TEMA5/Figure_1.png create mode 100644 TEMA5/report.md create mode 100644 TEMA5/task.md diff --git a/TEMA4/report.md b/TEMA4/report.md index c0aeab8..229254a 100644 --- a/TEMA4/report.md +++ b/TEMA4/report.md @@ -1,4 +1,4 @@ -# Протокол по Теме 2 +# Протокол по Теме 4 Марков Никита Сергеевич, А-03-23 diff --git a/TEMA5/Figure_1.png b/TEMA5/Figure_1.png new file mode 100644 index 0000000000000000000000000000000000000000..067118a5075cc3bfd280e6230087bb4f95b252ad GIT binary patch literal 29718 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porog==4: + dohod=2 +elif porog==5: + dohod=3 +else: + dohod=0 + + +>>> dohod +0 + +``` + +### Условные инструкции в одну строку + +```py + +>>> dohod=2 if porog>=4 else 0 +>>> dohod +2 +>>> if porog>=5 : rashod1=6; rashod2=0 + +>>> rashod1 +6 +>>> rashod2 +0 + +``` + +## 3.Управляющая инструкция for + +### 3.1 Простой цикл. + +```py + +>>> temperatura=5 +>>> for i in range(3,18,3): + temperatura+=i + + +>>> temperatura +50 + +``` + +### 3.2 Более сложный цикл + +```py + +>>> sps=[2,15,14,8] +>>> for k in sps: + if len(sps)<=10:sps.append(sps[0]) + else:break + + +>>> sps +[2, 15, 14, 8, 2, 2, 2, 2, 2, 2, 2] +>>> sps=[2,15,14,8] +>>> for k in sps[:]: + if len(sps)<=10:sps.append(sps[0]) + else:break + + +>>> sps +[2, 15, 14, 8, 2, 2, 2, 2] + +``` + +### 3.3 + +```py + +>>> import random as rn +>>> sps5=[] +>>> for i in range(10): + sps5.append(rn.randint(1,100)) + ss=sum(sps5) + if ss>500: break +else: + print(ss) + + +>>> ss +531 +>>> sps5 +[16, 30, 74, 91, 77, 97, 40, 38, 8, 60] +>>> for i in range(10): + sps5.append(rn.randint(1,100)) + ss=sum(sps5) + if ss>500: break +else: + print(ss) + + +>>> ss +578 +>>> for i in range(10): + sps5.append(rn.randint(1,100)) + ss=sum(sps5) + if ss>500: break +else: + print(ss) + + +>>> ss +607 +>>> sps5 +[16, 30, 74, 91, 77, 97, 40, 38, 8, 60, 47, 29] + +``` + +### 3.4. Пример с символьной строкой + +```py + +>>> stroka='Это – автоматизированная система' +>>> stroka1="" +>>> for ss in stroka: + stroka1+=" "+ss + + +>>> stroka1 +' Э т о – а в т о м а т и з и р о в а н н а я с и с т е м а' + +``` + +### 3.5 Запись цикла в строке. + +```py + +>>> import math +>>> sps2=[math.sin(i*math.pi/5+2) for i in range(100)] +>>> sps2 +[0.9092974268256817, 0.49103209793281005, -0.11479080280322804, -0.6767675184643197, -0.9802420445539634, -0.9092974268256817, -0.49103209793281016, 0.11479080280322791, 0.6767675184643196, 0.9802420445539634, 0.9092974268256818, 0.4910320979328103, -0.1147908028032278, -0.6767675184643196, -0.9802420445539632, -0.9092974268256818, -0.4910320979328104, 0.11479080280322768, 0.6767675184643195, 0.9802420445539632, 0.9092974268256819, 0.4910320979328105, -0.11479080280322579, -0.6767675184643194, -0.9802420445539632, -0.9092974268256819, -0.4910320979328106, 0.11479080280322743, 0.6767675184643193, 0.9802420445539632, 0.909297426825682, 0.49103209793281066, -0.1147908028032273, -0.6767675184643192, -0.9802420445539632, -0.909297426825682, -0.4910320979328108, 0.11479080280322719, 0.6767675184643192, 0.9802420445539631, 0.9092974268256822, 0.491032097932814, -0.11479080280322707, -0.676767518464319, -0.9802420445539625, -0.9092974268256822, -0.491032097932811, 0.11479080280323047, 0.6767675184643189, 0.9802420445539625, 0.9092974268256822, 0.4910320979328142, -0.11479080280322682, -0.6767675184643215, -0.9802420445539631, -0.9092974268256808, -0.4910320979328112, 0.11479080280322317, 0.6767675184643187, 0.9802420445539624, 0.9092974268256823, 0.4910320979328082, -0.11479080280322658, -0.6767675184643213, -0.980242044553963, -0.9092974268256838, -0.49103209793281144, 0.11479080280322293, 0.6767675184643186, 0.9802420445539637, 0.9092974268256824, 0.49103209793280844, -0.11479080280322633, -0.6767675184643158, -0.980242044553963, -0.9092974268256839, -0.49103209793281166, 0.11479080280322974, 0.6767675184643184, 0.9802420445539637, 0.9092974268256825, 0.4910320979328149, -0.11479080280321903, -0.6767675184643209, -0.9802420445539629, -0.909297426825681, -0.4910320979328119, 0.11479080280322244, 0.6767675184643129, 0.9802420445539636, 0.9092974268256826, 0.49103209793281505, -0.11479080280322584, -0.6767675184643155, -0.9802420445539644, -0.9092974268256812, -0.49103209793281205, 0.1147908028032222, 0.6767675184643127, 0.980242044553965] + +``` + +## 4.Управляющая инструкция while + +### 4.1. Цикл со счетчиком. +```py + +>>> rashod=300 +>>> while rashod: + print("Расход=",rashod) + rashod-=50 + + +Расход= 300 +Расход= 250 +Расход= 200 +Расход= 150 +Расход= 100 +Расход= 50 + +``` + +### 4.2. Пример с символьной строкой + +```py + +>>> import math +>>> stroka='Расчет процесса в объекте регулирования' +>>> i=0 +>>> sps2=[] +>>> while i + +### 4.3 Определение, является ли число простым + +```py + +>>> chislo=267 +>>> kandidat =chislo // 2 +>>> while kandidat > 1: + if chislo%kandidat == 0: # Остаток от деления + print(chislo, ' имеет множитель ', kandidat) + break # else выполняться не будет + kandidat -= 1 +else: # При завершении цикла без break + print(chislo, ' является простым!') + + +267 имеет множитель 89 + +``` + +### 4.4 Инструкция continue + +```py + +>>> number = 0 +>>> while number < 10: + number += 1 + if number % 2 == 0: # Если число четное + continue # Пропускаем оставшуюся часть цикла + print(f"Нечетное число: {number}") + + +Нечетное число: 1 +Нечетное число: 3 +Нечетное число: 5 +Нечетное число: 7 +Нечетное число: 9 + +``` + + + + + + + diff --git a/TEMA5/task.md b/TEMA5/task.md new file mode 100644 index 0000000..e5f8d4e --- /dev/null +++ b/TEMA5/task.md @@ -0,0 +1,35 @@ +# Общее контрольное задание по теме 4 + +Марков Никита Сергеевич, А-03-23 + +## Задание + +1.Для заданной символьной строки с англоязычным текстом (его можно заимствовать из помощи) определите порядковый номер каждой буквы в английском алфавите. + +2.Создайте список со словами из задания данного пункта. Для этого списка – определите, есть ли в нем некоторое заданное значение, и выведите соответствующее сообщение: либо о нахождении элемента, либо о его отсутствии в списке (проверить как с имеющимся, так и с отсутствующим словом). + +3.Создайте список студентов вашей группы (3-4 фамилии) и список их средних баллов в летней сессии – в порядке перечисления студентов в первом списке. Создайте еще 2 аналогичных списка для тех же студентов, но в другом порядке, по зимней сессии. Напишите инструкции, позволяющие по указанной (запрошенной и введенной) фамилии студента вывести его средние баллы по двум сессиям. + +## Решение + +```py + + + +``` + + + + + + + + + + + + + + + +